题目
July 6, 2021 · View on GitHub
The binomial coefficient C(n, k) has been extensively studied for its importance in combinatorics. Binomial coefficients can be recursively defined as follows:
C(n, 0) = C(n, n) = 1 for all n > 0;
C(n, k) = C(n − 1, k − 1) + C(n − 1, k) for all 0 < k < n.
Given n and k, you are to determine the parity of C(n, k).
输入描述
The input contains multiple test cases. Each test case consists of a pair of integers n and k (0 ≤ k ≤ n < 231, n > 0) on a separate line.
End of file (EOF) indicates the end of input.
输出描述
For each test case, output one line containing either a “0” or a “1”, which is the remainder of C(n, k) divided by two.
输入例子
1 1
1 0
2 1
输出例子
1
1
0
参考答案
#include<stdio.h>
int main()
{
int a, b;
while (scanf("%d%d", &a, &b) == 2) {
printf("%d\n", (a - b) & b ? 0 : 1);
continue;
int c = a - b;
int x = 0, y = 0, z = 0;
while (a = a >> 1) {
x += a;
}
while (b = b >> 1) {
y += b;
}
while (c = c >> 1) {
z += c;
}
if (x - y > z) printf("0\n");
else printf("1\n");
}
return 0;
}