给定一个二叉树，返回它的 后序 遍历。

示例:

输入: [1,null,2,3]  
   1
    \
     2
    /
   3 

输出: [3,2,1]

参考答案

class Solution {
public:
    void addPath(vector<int> &vec, TreeNode *node) {
        int count = 0;
        while (node != nullptr) {
            ++count;
            vec.emplace_back(node->val);
            node = node->right;
        }
        reverse(vec.end() - count, vec.end());
    }

    vector<int> postorderTraversal(TreeNode *root) {
        vector<int> res;
        if (root == nullptr) {
            return res;
        }

        TreeNode *p1 = root, *p2 = nullptr;

        while (p1 != nullptr) {
            p2 = p1->left;
            if (p2 != nullptr) {
                while (p2->right != nullptr && p2->right != p1) {
                    p2 = p2->right;
                }
                if (p2->right == nullptr) {
                    p2->right = p1;
                    p1 = p1->left;
                    continue;
                } else {
                    p2->right = nullptr;
                    addPath(res, p1->left);
                }
            }
            p1 = p1->right;
        }
        addPath(res, root);
        return res;
    }
};