README.md
December 5, 2022 ยท View on GitHub
Description
To split a string into pieces using a certain character as a delimiter. I do not want to get messages saying, "use the Split() function" as this isn't present in VB5.
Example of this is "hello to you", with the delimiter as " ". You'll get back 3 variables, one containing "hello", one containing "to" and one containing "you"
More Info
The string thats going to be split and the delimiter in which to split it with.
Put a button on a form, and leave it as the default name
An array of parsed words from the string
| Submitted On | |
| By | Danny Young |
| Level | Intermediate |
| User Rating | 4.3 (78 globes from 18 users) |
| Compatibility | VB 5.0, VB 6.0 |
| Category | String Manipulation |
| World | Visual Basic |
| Archive File |
Source Code
Option Explicit
Private Sub Command1_Click()
Dim A As Variant
Dim i As Integer
i = 1
A = Parse("hello to you", " ")
Do While A(i) <> ""
MsgBox A(i)
i = i + 1
Loop
End Sub
Public Function Parse(sIn As String, sDel As String) As Variant
Dim i As Integer, x As Integer, s As Integer, t As Integer
i = 1: s = 1: t = 1: x = 1
ReDim tArr(1 To x) As Variant
If InStr(1, sIn, sDel) <> 0 Then
Do
ReDim Preserve tArr(1 To x) As Variant
tArr(i) = Mid(sIn, t, InStr(s, sIn, sDel) - t)
t = InStr(s, sIn, sDel) + Len(sDel)
s = t
If tArr(i) <> "" Then i = i + 1
x = x + 1
Loop Until InStr(s, sIn, sDel) = 0
ReDim Preserve tArr(1 To x) As Variant
tArr(i) = Mid(sIn, t, Len(sIn) - t + 1)
Else
tArr(1) = sIn
End If
Parse = tArr
End Function