README.md

Description

Encrypts and decrypts strings

More Info

Simply:

DMEncrypt "Text"

and

DMDecrypt "Text"

Pretty straightforward

2 functions return a string value, either encrypted or decrypted text.

None that I know of

Submitted On
By	Micah Ellett
Level	Intermediate
User Rating	4.0 (8 globes from 2 users)
Compatibility	VB 3.0, VB 4.0 (16-bit), VB 4.0 (32-bit), VB 5.0, VB 6.0
Category	String Manipulation
World	Visual Basic
Archive File

Source Code

'THIS FUNCTION ENCRYPTS THE INPUT
Public Function DMEncrypt(strText As String)
On Error GoTo Xit
Dim Combine As String, i As Integer, Temp As String
Combine = ""
Temp = ""
For i = 1 To Len(strText) - 1 Step 2
  If Len(Trim(Str(Asc(Mid(strText, i, 1))))) < 3 Then
    Temp = "0" & Trim(Str(Asc(Mid(strText, i, 1))))
  Else
    Temp = Trim(Str(Asc(Mid(strText, i, 1))))
  End If
  Combine = Combine & Temp
  If Len(Trim(Str(Asc(Mid(strText, i + 1, 1))))) < 3 Then
    Temp = "0" & Trim(Str(Asc(Mid(strText, i + 1, 1))))
  Else
    Temp = Trim(Str(Asc(Mid(strText, i + 1, 1))))
  End If
  Combine = Combine & Temp
Next i
Temp = ""
For i = 1 To Len(Combine)
  Temp = Temp & Chr(Asc(Mid(Combine, i, 1)) + 128)
Next i
DMEncrypt = Temp
Clipboard.SetText Temp
Exit Function
Xit:
DMEncrypt = "{{ Error encrypting }}"
Exit Function
End Function
'THIS FUNCTION DECRYPTS THE INPUT
Public Function DMDecrypt(strText As String)
On Error GoTo Xit
Dim Combine As String, i As Integer, Temp As String, Temp2 As Integer
Combine = ""
For i = 1 To Len(strText)
  Combine = Combine & Chr(Asc(Mid(strText, i, 1)) - 128)
Next i
Temp = ""
For i = 1 To Len(Combine) Step 3
  Temp2 = Mid(Combine, i, 3)
  Temp = Temp & Chr(Temp2)
Next i
DMDecrypt = Temp
Exit Function
Xit:
DMDecrypt = "{{ Error encrypting }}"
Exit Function
End Function