README.md

Description

So you have built a cool web site with code you wrote or downloaded from great sites like planet-source-code, the next thing you might want to do is testing it: Can your code handle more than, say 10 concurrent users? Does it have a memory leak that will eventually lead to crash if you don't reboot?

Here is a java program I wrote that can query a web site continuously. If you want to simulate more than one user, just start as many instances of this program as you need. The command line to run it is:

java WebTest "http://www.yahoo.com/" 20000

This will query the www.yahoo.com site continuously, sleeping a random amount of time from 0 up to 20000 milliseconds between consecutive requests. If you omit the second parameter, the default number 10000 will be used.

More Info

Submitted On
By	nfs
Level	Advanced
User Rating	5.0 (15 globes from 3 users)
Compatibility	Java (JDK 1.1), Java (JDK 1.2)
Category	Complete Applications
World	Java
Archive File

Source Code

import java.net.*;
import java.io.*;
import java.util.*;
public class WebTest
{
  public static void main (String[] args)
  {
    // initialize random seed
    Random randomGen = new Random(new Date().getTime());
    while(true)
    {
      try
      {
        // sleep for a random interval
        Thread.currentThread().sleep(randomGen.nextInt(args.length>1?(new Integer(args[1]).intValue()):10000));
        if(args.length>0)
        {
          // print the user supplied URL to the console window
          System.out.println(args[0]);
          // open URL connection
          URLConnection urlConn = new URL(args[0]).openConnection();
          urlConn.setUseCaches(false);
          // read and print the content to the console window
          InputStream in = urlConn.getInputStream();
          byte buf[] = new byte[4096];
          int nSize = in.read(buf);
          while(nSize>=0)
          {
            System.out.print(new String(buf,0,nSize));
            nSize = in.read(buf);
          }
          System.out.print("\r\n");
        }
        else return;
      }
      catch(Exception e)
      {
        // print error message
        System.out.println("Exception: "+e.getMessage());
      }
    }
  }
}