11.md
August 14, 2021 · View on GitHub
@author jackzhenguo
@desc
@date 2019/2/15
11 次幂
base为底的exp次幂,如果mod给出,取余
In [1]: pow(2,1.5)
Out[1]: 2.8284271247461903
In [1]: pow(3, 2, 4) # 3的2次方结果再对4取余数
Out[1]: 1