Lesson-8.md
May 15, 2013 · View on GitHub
Lesson 8 Find 9 in number 1 to 100 1到100有多少个9
/*
* main.c - find how many digit 9 from 1 to 100
*
* Copyright (C) AKAE - li ming <limingth@gmail.com>
*
*/
#include <stdio.h>
/*
* find - calculate how many digit in num
* @num: the number we want to find
* @digit: the digit we search in num
*
* Return value: how many digit in this num
*
*/
int find(int num, int digit)
{
int counter = 0; /* the result of how many digit in num */
do {
/* get the last digit of num */
if (num % 10 == digit)
counter++;
/* get rid of the last digit */
num = num / 10;
} while (num != 0);
return counter;
}
int main(void)
{
int begin = 1; /* the begin number */
int end = 100; /* the end number */
int i = 0;
int sum = 0; /* the result of sumary */
/* calculate how many 9 in 1 to 100 */
for (i = begin; i <= end; i++) {
sum += find(i, 9);
}
printf("sum = %d \n", sum);
return 0;
}
知识点
- 函数 Function
- 形参和实参
- 函数返回值
- 逻辑分解
- 注释的写法
课堂讨论
- 示例中的 0, 100 为何要用 begin, end 来定义,直接写在 for 循环中可以吗?
- find 中的 do-while 改成 while 可以吗?
- 为什么不写一个函数,直接就能计算出1-100中的9的个数?
课后练习
- 求1-100以内最大的素数,要求用设计一个函数实现。
- 用户输入两个数字,按从个位对齐的方式,找出这2个数在相同位置处数字也相同的个数。
例如:123 和 5173 这2个数字,位置相同数字也相同的个数是 2
名人名言
- Brian W.Kernighan (C Programming Language 一书合作者)
- ”I don't think that I have any special insight, but it has always seemed to me best to do something that you really enjoy doing. If you have a job that is fun, where you are eager to start in the morning and hate to quit in the evening, that's what you want.“
- 我不认为自己有任何特别的远见,但是对于我来说做自己喜欢的事情似乎是最好的。如果你有一份有趣的工作,在早上你非常渴望开始做,并且在傍晚的时候你又不愿停下来,那这就是你想要的。