(C++) Answer of exercise \#9: No for-loops \#24

This is the answer of Exercise #9: No for-loops.

Question #24: SumSecond

Replace the for-loop. You will need:

• boost::bind
• std::plus

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int SumSecond(const std::vector<std::pair<int,int> >& v) {   const int size = static_cast<int>(v.size());   int sum = 0;   for (int i=0; i!=size; ++i)   {     sum+=v[i].second;   }   return sum; }

Answer using STL only

You may contact me if you have an STL solution...

Answer using Boost.Bind

Thanks to 'ofwolfandman':

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#include <functional> #include <numeric> #include <utility> #include <vector> #include <boost/bind.hpp> int SumSecond(const std::vector<std::pair<int,int> >& v) {   return std::accumulate(     v.begin(),     v.end(),     static_cast<int>(0),     boost::bind(       std::plus<int>(),       _1,       boost::bind<int>(&std::pair<int,int>::second, _2)       )     ); }

Answer using Boost.Lambda

Thanks to 'ofwolfandman':

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#include <functional> #include <numeric> #include <utility> #include <vector> #include <boost/lambda/lambda.hpp> #include <boost/lambda/bind.hpp> int SumSecond(const std::vector<std::pair<int,int> >& v) {   return std::accumulate(     v.begin(),     v.end(),     static_cast<int>(0),     boost::lambda::_1     + boost::lambda::bind(       &std::pair<int, int>::second, boost::lambda::_2       )   ); }